4x^2-1452x+131040=0

Solution for 4x^2-1452x+131040=0 equation:

4x^2-1452x+131040=0

a = 4; b = -1452; c = +131040;
Δ = b2-4ac
Δ = -14522-4·4·131040
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1452)-108}{2*4}=\frac{1344}{8}
=168
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1452)+108}{2*4}=\frac{1560}{8}
=195
$